Question

The given line passes through the points (0,-3
) and (2, 3).

On a coordinate plane, a line goes through (0, negative 3) and (2, 3). A point is at (negative 1, negative 1).

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (-1,-1)?

Answer 1

The equation of the line in the point-slope form, of the line that is parallel to the provided line and passes through the point (-1,-1) is (y -1) = 3(x + 1)

What is a straight line?

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

$\rm m =\dfrac{y_2-y_1}{x_2-x_1}$

We have:

The given line passes through the points (0,-3) and (2, 3).

$\rm y\ -\ 3\ =\ \dfrac{6}{2}\left(x-2\right)$

y = 3x - 6 + 3

y = 3x - 3

The slope of the parallel line:

m = 3

Passes through (-1, 1)

(y -1) = 3(x + 1)

The above equation is in the point-slope form

Thus, the equation of the line in the point-slope form, of the line that is parallel to the provided line and passes through the point (-1,-1) is (y -1) = 3(x + 1)

Learn more about the straight line here:

brainly.com/question/3493733

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