Answer:
Step-by-step explanation:
[tex]-\frac{9}{3} + b = -1[/tex]
=> [tex]-\frac{9}{3} + b = -1[/tex]
=> -3 + b = -1
=> b = 3 - 1
=> b = 2
Hence,
The value of b is 2 (Ans)
Now,
Putting the value of b = 2 in the given equation we get,
LHS = [tex]-\frac{9}{3} + 2[/tex]
= [tex]\frac{-9 + 6}{3}[/tex]
= [tex]-\frac{3}{3}[/tex]
= -1
RHS = -1
As,
LHS = RHS.
Hence,
The given value of b = 2 is appropriate. (Proved)