Question

Hey guys need help here

Answer 1

Answer:

$\boxed {D) -\frac{2y}{x}}$

Step-by-step explanation:

Solving :

$\implies \mathsf {\frac{(-2xy^{2})^{3}}{4x^{4}y^{5}}}$

$\implies \mathsf {\frac{-8x^{3}y^{6}}{4x^{4}y^{5}}}$

$\implies \mathsf {\frac{-2y}{x}}$