DF=
Help me please:))

Answer:
[tex]\fbox {DF = 20}[/tex]
Step-by-step explanation:
Given :
Step 1 : Find RT
Step 2 : Find SF
Step 3 : Find RY
Step 4 : Find TY
Step 5 : Find DF
Answer:
DF = 20
Step-by-step explanation:
Triangle SDF has side lengths SD, DF, SF.
Triangle RTY has side lengths
RT = (9/4)SD
RY = (9/4)SF
TY = (9/4)DF
"SF is 2 less than RT" Given
SF = RT - 2
SF = (9/4)SD - 2
"SD = 8" Given
SF = (9/4)(8) - 2
SF = 16
"TY is 9 more than RY" Given
TY = RY + 9
(9/4)DF = (9/4)SF + 9
(9/4)DF = (9/4)(16) + 9
(9/4)DF = 45
DF = 45 × 4/9
DF = 20