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Answer:

[tex]\fbox {DF = 20}[/tex]

Step-by-step explanation:

Given :

  • ΔSDF ~ ΔRTY = 4 : 9 (Ratio of similitude)
  • SF = RT - 2
  • TY = RY + 9
  • SD = 8

Step 1 : Find RT

  • SD : RT = 4 : 9
  • 8 : RT = 4 : 9
  • RT = 18

Step 2 : Find SF

  • SF = RT - 2
  • SF = 18 - 2
  • SF = 16

Step 3 : Find RY

  • SF : RY = 4 : 9
  • 16 : RY = 4 : 9
  • RY = 36

Step 4 : Find TY

  • TY = RY + 9
  • TY = 36 + 9
  • TY = 45

Step 5 : Find DF

  • DF : TY = 4 : 9
  • DF : 45 = 4 : 9
  • DF = 20

Answer:

DF = 20

Step-by-step explanation:

Triangle SDF has side lengths SD, DF, SF.

Triangle RTY has side lengths

RT = (9/4)SD

RY = (9/4)SF

TY = (9/4)DF

"SF is 2 less than RT" Given

SF = RT - 2

SF = (9/4)SD - 2

"SD = 8" Given

SF = (9/4)(8) - 2

SF = 16

"TY is 9 more than RY" Given

TY = RY + 9

(9/4)DF = (9/4)SF + 9

(9/4)DF = (9/4)(16) + 9

(9/4)DF = 45

DF = 45 × 4/9

DF = 20

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