Question

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of unit(s) and a across the -axis.

Answer 1

We can show that ΔABC is congruent to ΔA'B'C' by a translation of 2 unit(s) left and a reflection across the x-axis.

How to explain the transformation?

The given triangles ABC and A'B'C' are congruent. If we make a point A of ΔABC and A' of ΔA'B'C' then we get the coordinates of A as (8,8) and A' (6,-8)

Therefore, shifting of A to A' = (8 - 6) = 2 units on x-axis and no translation in y-coordinates. Hence, the translation of 2 units left has occurred.

In addition to this ΔABC is reflected by the x-axis to form A'B'C'.

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