What is the value of x?

[tex]\huge\underline{ Answer -}[/tex]
From the figure ,
it is quite clear that the given triangle is an isosceles , right-angled triangle
Given that , one side of the triangle is of length 3√2 and the other one is of length " x " units.
therefore ,
By applying Pythagoras theorem ,
[tex]x {}^{2} + x {}^{2} = (3 \sqrt{2} ) {}^{2} \\ \\ 18 = 2x {}^{2} \\ \\ x {}^{2} = \cancel \frac{18}{2} = 9 \: units \\ \\ \therefore \: \boxed{x = 3 \: units}[/tex]
thus ,
option ( B ) is correct.
hope helpful ~