During track practice, Yi finished the 100-meter dash with times of 16.2 seconds, 16.6 seconds, and 15.6 seconds. She ran one more time before the end of track practice and finished in 15.6 seconds. What is the mean absolute deviation of Yi's times?
A. 0.2 seconds
B. 0.4 seconds
C. 1.6 seconds
D. 0.53 seconds

Respuesta :

Using it's formula, the mean absolute deviation of Yi's times was of:

B. 0.4 seconds.

What is the mean absolute deviation of a data-set?

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

In this problem, the mean is given by:

M = (16.2 + 16.6 + 15.6 + 15.6)/4 = 16

Hence the mean absolute deviation is of:

MAD = (|16.2 - 16| + |16.6 - 16| + |15.6 - 16| + |15.6 - 16|)/4 = 0.4.

Hence option B is correct.

More can be learned about the mean absolute deviation at https://brainly.com/question/3250070

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