The rocket peaks at 1170.77 meters above sea level.
What is a quadratic equation?
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
Given function;
0 = -4,9t2 + 139t + 185
By using the quadratic formula,
t = -1.27 or 29.64 seconds
since time can't be negative
t = 29.64 secs
h(t) is maximum
[d{h(t)}}/dt = -9.8t + 139
at h(t) maximum, [d{h(t)}}/dt is 0
0 = -9.8t + 139
9.8t = 139
t = 14.18 secs
Substituting,
h(t) = – 4.9t2 + 139t + 185
h(t) = -4.9(14.18^2) + 139(14.18) + 185
h(t) = 1170.77 m
Hence, The rocket peaks at 1170.77 meters above sea level.
Learn more about quadratic equations;
brainly.com/question/13197897
The complete question is
"NASA launches a rocket at t = 0 seconds. Its height, in meters above sea level, as a function of time is given by h(t) = – 4.9t2 + 139t + 185,
Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
The rocket splashes down after seconds. How high above sea level does the rocket get at its peak? The rocket peaks at meters above sea level. the splash down occurs when h(t) = 0"
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