Answer: [tex]\left(\frac{1}{2}, 1 \right), (1, 2)[/tex]
Step-by-step explanation:
We have [tex]y=2x^{2}[/tex] and [tex]y=3x-1[/tex].
Since both of the equations are set equal to y, we can conclude that:
[tex]2x^2 = 3x-1\\\\2x^{2}-3x+1=0\\\\(2x-1)(x-1)=0\\\\x=\frac{1}{2}, 1[/tex]
If [tex]x=\frac{1}{2}[/tex], then [tex]y=3\left(\frac{1}{2} \right)-1=1[/tex]
If [tex]x=1[/tex], then [tex]y=3-1=2[/tex]
Therefore, the solutions are [tex]\left(\frac{1}{2}, 1 \right), (1, 2)[/tex]
