Question

AB is a common external tangent to circles D and C. The points of tangency are at A and B. DC = 13, BC = 2 and AD = 7.
Find AB.

Answer 1

Based on the calculations, the length of side AB is equal to 13.93 units.

How to find the length of AB?

Since the points of tangency are at A and B, we would determine the side length of the point lying between side A and D as follows:

AM = AD - BC

AM = 7 - 2

AM = 5 units.

Now, we can determine the length of side AB by applying Pythagorean's Theorem:

AB² = BM² + AM²

AB² = 13² + 5²

AB² = 169 + 25

AB = √194

AB = 13.93 units.

Read more on Pythagorean theorem here: https://brainly.com/question/23200848

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