answer:
g(x)= 3^(x-2) -1
Step-by-step explanation:
f(x)= 3^x
g(x)= 3^(x+a) + b
with plot points (2,0) & (3,2)
g(x) is y or 0 & 2
x in g(x)= 3^(x+a) + b are x values in the plot points 2 & 3
with x & y values you have to figure out a & b
g(x)= 3^(x+a) + b
subtract :
0= 3^(2+a) + b
2= 3^(3+a) + b
0= 3^(2+a) + b
-2= -3^(3+a) - b
-2 = 3^(2+a) - 3^(3+a)
-2 = 3^2 3^a - 3^3 * 3^a
-2 = 9 3^a - 27 * 3^a
-2 = (9 - 27) * 3^a
-2 = (-18) * 3^a
-2/-18 = 3^a
1/9 = 3^a
a = -2
put a = -2 back into the second equation
3^(3+a) + b = 2
3^(3-2) + b = 2
3^(1) + b = 2
3 + b = 2
b = -1
g(x)= 3^(x-2) -1
https://brainly.com/question/11641965
