Question

(02.01 LC)

PLEASE HURRY
ACAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps
point C to C' (3, 2). Find the coordinates of A' and R' under this
translation. (6 points)
A. A' (4, -2); R' (2, -1)
B. A' (-2, 2); R' (2,-2)
C. A' (2, -1); R' (4, -2)
D. A' (-1, 0); R' (-2, 2)

Answer 1

Answer: Choice C

A' (2, -1); R' (4, -2)

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Explanation:

Going from C(2,4) to C'(3,2) means we do these two things (in any order)

• Shift 1 unit to the right
• Shift 2 units down

We can write that rule using the notation $(x,y) \to (x+1, y-2)$

Whatever the x coordinate is, add 1 to it. Also subtract 2 from the y coordinate.

Here are the steps you could show how point A(1,1) is moving

$(x,y) \to (x+1, y-2)\\\\(1,1) \to (1+1, 1-2)\\\\(1,1) \to (2, -1)$

Therefore, the point A(1,1) will move to A'(2, -1)

And the point R(3,0) moves to R'(4, -2) through similar steps.

$(x,y) \to (x+1, y-2)\\\\(3,0) \to (3+1, 0-2)\\\\(3,0) \to (4, -2)$

The diagram is shown below.