Question

In an isolated population of sneeches, Homozygous dominant (SS) and heterozygous (Ss) sneeches have a star on their bellies. Homozygous recessive (ss) individuals have plain bellies (no stars). In a population of 125 total sneeches, 88 sneeches have stars on their bellies. Assume the conditions for applying the Hardy Weinberg equation have been met. Grab a calculator and calculate the answers following questions – you must show your work for full credit.

-How many individuals are homozygous dominant (SS) for this trait?

-How many individuals are heterozygous (Ss) for this trait?

-How many individuals are homozygous recessive (ss) for this trait?

Answer 1

Based on the Hardy-Weinberg equations:

• Individuals homozygous dominant (SS) for the trait  = 26

• Individuals heterozygous (Ss) for the trait = 62
• Individuals homozygous recessive (SS) for the trait = 37

What is the Hardy-Weinberg equation?

The Hardy-Weinberg equations are given as follows:

• p² + 2pq + q² = 1
• p + q = 1

From the data given:

p² + 2pq = 88/125

q² = (125 - 88)/125

q² = 37/125

q² = 0.296

q = 0.54

p = 1 -q

p = 1 - 0.54

p = 0.46

Frequency of Individuals homozygous dominant (SS) for the trait, $p^{2}$ = 0.2116

Individuals homozygous dominant (SS) for the trait = 0.2116 * 125 = 26 individuals

Individuals heterozygous (Ss) for the trait = 88 - 26 = 62

Individuals homozygous recessive (SS) for the trait = 37

Learn more about Hardy-Weinberg equation at: https://brainly.com/question/5028378

#SPJ1