The values of the trigonometry ratios are:
- cos α = - 5/13 and cot α = 5/12
- cot α = -5/12 and sec α = 13/5
How to solve the trigonometry ratios?
1: sin α = -12/13 and tan α > 0, find cos α and cot α
Because tan α > 0, then it means that cos α and sin α are negative
So, we have:
sin²α + cos²α = 1
Substitute sin α = -12/13
(-12/13)² + cos²α = 1
This gives
cos²α = 1 - (-12/13)²
Evaluate the squares
cos²α = 1 - 144/169
Evaluate the difference
cos²α = 25/169
Take the square root of both sides
cos α = - 5/13
The cotangent ratio is represented as:
cot α = cos α/sin α
This gives
cot α = (-5/13)/(-12/13)
Evaluate
cot α = 5/12
Hence, cos α = - 5/13 and cot α = 5/12
2: tan α = -12/5 for α in quadrant IV, find sec α and cot α
Because α is in quadrant IV, then it means that sec α is positive
cot α = 1/tan α
This gives
cot α = 1/(-12/5)
Evaluate
cot α = -5/12
Also, we have:
sec²α = 1 + tan²α
Substitute tan α = -12/5
sec²α = 1 + (-12/5)²
Evaluate the squares
sec²α = 1 + 144/25
Evaluate the sum
sec²α = 169/25
Take the square root of both sides
sec α = 13/5
Hence, cot α = -5/12 and sec α = 13/5
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