The zero of the equation is 0. Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0
Asymptotes and zeros of a function
The zero of the function is the point where the function is zero
Given the function below
f(x) = 4x/x-16
For the zeros
0 = 4x/x -16
4x = 0
x = 0
Hence the zero of the equation is 0
The vertical asymptote is the point where the denominator is zero
x - 16 = 0
x = 16
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0
Learn more on asymptotes and zeros here: https://brainly.com/question/16948935
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