Answer: [tex]-\frac{3}{2} \leq x < 5[/tex]
Step-by-step explanation:
We can split this into two inequalities, namely [tex]2x-3 < x+2[/tex] and [tex]x+2 \leq 3x+5[/tex].
Solving the first inequality,
[tex]2x-3 < x+2\\\\x-3 < 2\\\\x < 5[/tex]
Solving the second inequality,
[tex]x+2 \leq 3x+5\\\\2 \leq 2x+5\\\\-3 \leq 2x\\\\-\frac{3}{2} \leq x[/tex]
So, the solution is [tex]-\frac{3}{2} \leq x < 5[/tex]
