Question

Two very large charged parallel metal plates are 13.0 cm c m apart and produce a uniform electric field of 3.40×106 N/C N / C between them. A proton is fired perpendicular to these plates with an initial speed 5.20 km/s k m / s , starting at the middle of the negative plate and going toward the positive plate.

Answer 1

The work done by the electric field on the proton when it reaches the positive plate willl be 9.1 ×10⁻¹⁵ J.

What is an electric field?

A physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them, is referred to as an electric field,

The electric field formula is as follows:

E = F /Q

Where,

The electric field is denoted by the letter E.

F is a powerful letter.

The charge is Q.

The potential difference between the plate;

$\rm V = E d \\\\ V = 3.40 \times 10^6 \times 0.13 \ m \\\\ V= 442000 \\\\ V = 4.42 \times 10^5 \ v$

Force on the charged particle ;

$\rm F = qV \\\\ F= 1.6 \times 10^{-19} \times 4.42 \times 10^ 5 \\\\\ F = 7.0 \times 10^{-14} \ N$

Work done in  order to move the charge;

$\rm W = F \times d \\\\ W= 7.0 \times 10^{-14} \ N \times 0.13 m \\\\ W=9.1 \times 10^{-15} \ J$

Hence, the work done by the electric field on the proton when it reaches the positive plate willl be 9.1 ×10⁻¹⁵ J.

The complete question is attached in attachments.

To learn more about the electric field refer to the link;

https://brainly.com/question/26690770

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