urgent help wanted/ needed

The equation in slope-intercept form is: y = -x + 5
The equation in point-slope form is: y - 3 = -1(x - 2)
Slope (m) = rise/run = -(2/2) = -1
Y-intercept (b) = 5 (where the line intercepts the y-axis)
Using a point, (2, 3) = (a, b) and m = -1, the equation in point-slope form is:
y - 3 = -1(x - 2)
Rewrite in slope-intercept form:
y - 3 = -x + 2
y = -x + 2 + 3
y = -x + 5
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