Question

help!!

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist examining seven people until he finds the first patient who has an ingrown toenail?

a.) (0.33)6
b.) (0.67)6
c.) (0.33)6(0.67)1
d.) (0.67)6(0.33)1
e.) 1 − (0.33)6

Answer 1

The probability of a podiatrist examining seven people until he finds the first patient who has an ingrown toenail is (0.67)^6 * (0.33)^1

How to determine the probability?

The probability that a person has an ingrown toenail is:

p = 33%

This gives

p = 0.33

Using the complement rule, the probability that a person does not have an ingrown toenail is:

q = 1 - 0.33

q = 0.67

When he examines 7 people before he sees a patient with an ingrown toenail, the event is represented as:

P = q^6 * p

So, we have:

P = (0.67)^6 * (0.33)^1

Hence, the probability is (0.67)^6 * (0.33)^1

Read more about probability at:

https://brainly.com/question/25870256

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