Question

A baseball is thrown at angle of 65 degrees with an initial velocity of 45 m/s. How long will the baseball remain in the air?
Assume yi = yf =0 m
G= -9.81 m/s^2

A) 4.15 seconds
B) 8.31 seconds
C) 9.37 seconds
D) 1.44 seconds

Answer 1

The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.

What is the maximum height achieved in projectile motion?

It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.

From Newton's first equation of motion;

$\rm v_y= u_y+gt \\\\ 0 = usin \theta - gt \\\\ t = \frac{u sin\theta }{g}\\\\t = 4.68 \ sec$

The time the baseball remains in the air will be twice the time he travels for one side motion;

T' = 2t

T'=2 × 4.68 sec

T'= 9.37 sec

Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.

To learn more about the projectile motion refer to the link;

https://brainly.com/question/6261898

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