Answer:
the distance between DE is 2
The distance of EF is 5
The distance of FD is [tex]\sqrt{29}[/tex]
Perimeter is 7+[tex]\sqrt{29}[/tex]
Step-by-step explanation:
Distance of DE
[tex]\sqrt{(-3-(-3))^2+(3-1)^2}[/tex]
sqrt([tex](-3+3)^2+(2)^2[/tex])
sqrt([tex](0)^2+4[/tex])
[tex]\sqrt{4}[/tex]
=2
Distance of EF
[tex]\sqrt{(2-(-3))^2+(3-3)^2}[/tex]
Solve that like DE and it equals 5
Distance of FD
[tex]\sqrt{(2-(-3))^2+(3-1)^2}[/tex]
equals to [tex]\sqrt{29}[/tex]
P=DE+EF+FD
P=2+5+[tex]\sqrt{29}[/tex] = 7+[tex]\sqrt{29}[/tex]
