Question

which expression is equivalent to (tan(theta/2))(-sin theta)

Answer 1

Answer:

Step-by-step explanation:

$(tan\frac{\theta}{2} )(-sin\theta)\\=(\frac{sin~\frac{\theta}{2} }{cos\frac{\theta}{2} } )(-2sin\frac{\theta}{2} cos\frac{\theta}{2})\\=-2sin ^2 \frac{\theta}{2} \\=cos ~2 \theta-1$