Question

A 45. 5-g super ball traveling at 27. 5 m/s bounces off a brick wall and rebounds at 21. 0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3. 30 ms, what is the magnitude of the average acceleration of the ball during this time interval?.

Answer 1

The magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².

What is acceleration?

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 27.5 m/s

Rebound velocity, v= 21.0 m/s

Time elapsed, t = 3.30 × 10⁻³ seconds.

To find ;

Average acceleration, a

The average acceleration when the change in velocity is observed by the formula as:

$\rm a_{avg}= \frac{v-u}{t}$

Substitute the given values:

$\rm a_{avg}= \frac{27.5-21.0}{3.30 \times 10^{-3}} \\\\ a_{avg}= 1969.69 \ m/s^2$

Hence, the magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².

To learn more about acceleration, refer to the link https://brainly.com/question/2437624#SPJ1.

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