The exact value of [tex]\dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})}[/tex] would be root 2.
The function is a type of relation, or rule, that maps one input to specific single output.
Given;
[tex]\dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})}[/tex]
We know that
The inverse tan(-1) = -π/4
cos(-π/4) = 1/√2
The inverse cos(√3/2) = π//6
sin(π/6) = 1/2
Then substitute
[tex]\dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})}\\\\[/tex]
[tex]\dfrac{(1/\sqrt{2}) }{(1/2)} \\\\= \sqrt{2}[/tex]
Learn more about function here:
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