Question

The reaction of nitrogen(g) with hydrogen(g) to form ammonia(g) proceeds as follows: N2(g) 3H2(g)2NH3(g) When 6.44 grams of N2(g) react with sufficient H2(g), 21.2 kJ of energy are evolved. What is the value of H for the chemical equation given

Answer 1

The enthalpy of the reaction is obtained as 4.876 kJ.

What is the enthalpy?

The enthalpy of a reaction is the heat that is absorbed or emitted in a reaction.

Given the reaction; N2(g) + 3H2(g) ⇔2NH3(g);

Number of moles of N2 = 6.44 grams/28 g/mol

= 0.23 moles

If 1 mole of N2 releases 21.2 kJ of energy

0.23 moles of N2 releases 0.23 moles *  21.2 kJ /1 mole

= 4.876 kJ

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