Question

PLEASE HELP ASAP!!!!!!!!!
Prove the trigonometric identity.

tanx+cotx/cscx cosx=sec^2x

Drag an expression to each box to correctly complete the proof.

Answer 1

The proof will be given as:- $\dfrac{tanx+Cotx}{Coscx Cosx} = Sec^2x$.

What is trigonometry?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The proof will be given as:-

$\dfrac{tanx+Cotx}{Coscx Cosx} = \dfrac{tanx}{coscxCosx}+\dfrac{Cosx}{CoscxCosx}$

     

$\dfrac{tanx+Cotx}{Coscx Cosx} =\dfrac{\dfrac{Sinx}{Cosx}}{\dfrac{Cosx}{Sinx}}+\dfrac{\dfrac{Cosx}{Sinx}}{\dfrac{Cosx}{Sinx}}$

$\dfrac{tanx+Cotx}{Coscx Cosx} = \dfrac{Sin^2x}{Cos^2x}+1$

$\dfrac{tanx+Cotx}{Coscx Cosx} = tan^2x+1}$

$\dfrac{tanx+Cotx}{Coscx Cosx} =Sec^2x$

Therefore the proof will be given as:- $\dfrac{tanx+Cotx}{Coscx Cosx} = Sec^2x$.

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