The standard deviation will be 6816.9645.
From the information given, the mean is 74000 and X is given as 60000.
P[(Z < (-60000 - 74000)/SD] = 0.02
Note that 0.02 will be -2.0537 under the normal distribution table.
-14000/SD = -2.0537
SD = -14000/-2.0537
SD = 6816.9645
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