Respuesta :
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Answer: [tex]\textsf{y = 4x - 12}[/tex]
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Given: [tex]\textsf{Slope = 4, Point = (2, -4)}[/tex]
Find: [tex]\textsf{The equation in slope-intercept form}[/tex]
Solution: We need to plug in the values into point-slope form and after simplifying, distributing, and solving for y we will have our equation in slope-intercept form.
Plug in the values
- [tex]\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}[/tex]
- [tex]\textsf{y - (-4) = 4(x - 2)}[/tex]
Distribute and simplify
- [tex]\textsf{y + 4 = 4(x - 2)}[/tex]
- [tex]\textsf{y + 4 = (4 * x) + (4 * -2)}[/tex]
- [tex]\textsf{y + 4 = 4x + (-8)}[/tex]
- [tex]\textsf{y + 4 = 4x - 8}[/tex]
Subtract 4 from both sides
- [tex]\textsf{y + 4 - 4 = 4x - 8 - 4}[/tex]
- [tex]\textsf{y = 4x - 8 - 4}[/tex]
- [tex]\textsf{y = 4x - 12}[/tex]
Using the information that was provided in the problem statement we were able to determine that the equation in slope-intercept form was y = 4x - 12.
Answer:
y = 4x - 12
Step-by-step explanation:
Given:
slope of 4, and point (2, -4)
Here, we're being asked to write the equation in Slope-Intercept Form. As we have been given the slope and a point on the line, we can use the Point-Slope Form to be able to find that equation.
First, know the two forms:
⇒ Point-Slope Form: y - y₁ = m(x - x₁)
where: m is the slope, and (x₁, y₁) is the given point
⇒ Slope-Intercept Form: y = mx + b
where: m is the slope, and b is the y-intercept
Now, substitute the given values into the Point-Slope Form:
⇒ y - y₁ = m(x - x₁)
⇒ y - (-4) = 4(x - 2) [simplify]
⇒ y + 4 = 4x - 8
Change to the Slope-Intercept Form:
⇒ y + 4 = 4x - 8 [subtract 4 from both sides]
⇒ y + 4 - 4 = 4x - 8 - 4
⇒ y = 4x - 12
Therefore, the equation of the line in slope-intercept form is: y = 4x - 12
Learn more about both forms here:
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