A 1-kg block starts sliding up a 30o inclined plane with an initial velocity of 4.00 m/s. How far will the block travel before coming to rest, if the surface is rough and the coefficient of kinetic friction between the block and the ramp is 0.2.

Respuesta :

The block will travel 2.038 m before stopping. Newton's third equation of motion is applied in the given problem.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically in the different components and balancing the equation gets.Components in the x-direction.

From Newton's third equation of motion;

v²=u²+2as

0 =u²+2(-a)s

u²=2as

u²=2×(2×μg)s

4.00 m/sec = √2×(2 ×0.2 ×9.81 s

16 = 7.848 s

s = 2.038 m

Hence, the block will travel 2.038 m before stopping.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663

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