The block will travel 2.038 m before stopping. Newton's third equation of motion is applied in the given problem.
It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration. Mathematically in the different components and balancing the equation gets.Components in the x-direction.
From Newton's third equation of motion;
v²=u²+2as
0 =u²+2(-a)s
u²=2as
u²=2×(2×μg)s
4.00 m/sec = √2×(2 ×0.2 ×9.81 s
16 = 7.848 s
s = 2.038 m
Hence, the block will travel 2.038 m before stopping.
To learn more about the friction force refer to the link;
https://brainly.com/question/1714663
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