Given: AC and BD are parallel. BX and CY are parallel. AX = DY.
Prove: AYC is congruent to DXB

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. Using the ASA congruency the triangles are congruent.
A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.
For the two of the given triangles ΔACY and ΔDXB,
Since the measure of the two angles and one side of the two triangles are equal, therefore, using the ASA congruency the triangles are congruent.
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