The number of moles of [tex]Na_2SO_4[/tex] form from 5.0 moles [tex]Na_2S[/tex] is 5 moles.
Limiting reactants are those reactants that are completely used up in a chemical reaction.
4.0 mol [tex]Na_2S[/tex] will be completely used since the combining ratio is 1 : 1 : 1.
[tex]Na_2S + CuSO_4[/tex] ->[tex]Na_2SO_4 + CuS[/tex]
From the chemical equation above, 5.0 moles [tex]Na_2S[/tex] will yield 5 moles of [tex]Na_2SO_4[/tex].
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