x = 2/3 , 0 .
Question :
[tex] {3x}^{2} - 2x = 0[/tex]
use quadratic formula :
[tex]x = \frac{( - b)± \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
Solution :
[tex]a {x}^{2} + bx + c = 0 \\ a = 3 \\ b = - 2 \\ c = 0[/tex]
[tex]x = \frac{ - ( - 2)± \sqrt{ { (- 2)}^{2} - 4 \times 3 \times 0} }{2 \times 3} \\ \\ x = \frac{2± \sqrt{4 - 0} }{6} \\ \\ x = \frac{2± \sqrt{4} }{6} \\ \\ x = \frac{2± 2}{6} [/tex]
separate into two equations :
[tex]x = \frac{2 + 2}{6} = \frac{4}{6} = \frac{2}{3} .[/tex]
[tex]x = \frac{2 - 2}{6} = \frac{0}{6} = 0.[/tex]
the values of x are 2/3 and 0 .