Area of the rectangle is 96.05 sq.units , The ratio of the areas is 2/3 , Area of rectangle ABEF is 64.03 sq.units.
The complete question is
In the figure, the ratio of the area of rectangle ABEF to the area of rectangle ACDF is(a)_____ . If the coordinates of point A are (0,6), the area of rectangle ABEF is(b)____ square units, and the area of rectangle ACDF is(c)____ square units. The perimeter of rectangle BCDE is(d)____ units.
A rectangle is a polygon with four sides and for angles and four vertices , Its opposite sides are parallel and equal.
The area of rectangle ACDF is square units. = ?
The perimeter of rectangle BCDE is units. = ?
[tex]\rm d = \sqrt{ (y_2 -y_1 )^2 + (x_2 -x_1)^2}\\\\\rm d = \sqrt{ (2 - 6 )^2 + (5 - 0)^2}[/tex]
d = 9.605
the length of [tex]\rm EF[/tex]
[tex]\rm FE[/tex] = 10 units.
and [tex]\rm FD[/tex] = 15 units
Area of a Rectangle [tex]\rm ACDF[/tex] is given by
Length x width
10 * 9.605
Area of the rectangle is 96.05 sq.units
Perimeter of a rectangle is = 2( length + breadth)
ED = FD-FE = 15- 10 = 5 units
Therefore
Perimeter = 2 ( 5 + √41 )
Perimeter = 22.81 units
Area of rectangle ABEF is 64.03 sq.units
The ratio of the areas
= 64.03/96.05
= 0.666667
= 2/3
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