NEED ANSWER ASAP!!!! Tony pulls a luggage cart at an angle of 30° to the horizontal. The luggage cart has a mass of 35 kg, and he pulls with a force of 75 N.

a. What is the normal force on the luggage cart?

b. What force would Tony need to apply at a 30° angle to pull the luggage cart completely off the ground?

c. How does your answer in part (b) change as the angle increases?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets.Components in the x-direction.

Given data;

The angle of pulling with horizontal. = 30°

Mass of luggage cart=35 kg

Pulling force= 75 N

The force in the y-direction;

N+Fsin30° = mg

N+75 sin 30° = 35 × 9.81

N=305.85 N

The force would Tony need to apply at a 30° angle to pull the luggage cart completely off the ground;

N-mg=Fsin30

Fsin30=75 sin 30

Fsin30=375 N

Hence the normal force on the luggage cart and force would Tony need to apply at a 30° angle to pull the luggage cart willl be 305.85 N and 375 N.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663

#SPJ1