The answers to the following question is
1) KL = 10
2) TE= 15 cm
3) angle PUT= 13
4) angle SQP = 21
What is similarity in triangle?
Two triangles are similar if they have the same ratio of corresponding sides and equal pair of corresponding angles. If two or more figures have the same shape, but their sizes are different, then such objects are called similar figures.
1) Using similarity property in given triangle
SR/ KI= SJ / JK
AS, JK= 2 SJ
SR/ KI= SJ / 2 SJ
5/ KI = 1/2
KL= 10
2) As, the diagonal of parallelogram bisect equally each other then
VE = TE
AS, VE = 15
So, TE= 15 cm
3) As, PU is the bisector of angle SUT
angle PUT= 1/2 (angle SUT)
PUT = 1/2 (26)
angle PUT= 13
4) As PQ is the bisector SQR
angle PQR= angle SQP = 21
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