267.14 gm grams[tex]Fe_2O_3[/tex] would be required to make 187 g Fe.
A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.
The balanced equation:
Fe₂O₃ + 3 CO ⟶ 3 CO₂ + 2 Fe
We know that the molecular mass of iron-oxide = 160 g/mole.
We know that the molecular mass of iron = 56 g/mole.
From the above reaction, we can say that
1 mole of iron -oxide produces 2 moles of iron
160 gm of iron oxide produce 112 gm of iron
So,
1 gm of iron required 160÷112 =1.42 gram of iron oxide
Therefore,
187 gm of iron required 1.42 x 187 =265.54 of iron oxide.
Therefore 187 gm of iron required 267.14 iron oxide.
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