266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
How to calculate mass?
The mass of a product or reactant can be calculated using stoichiometry as follows:
According to this question, iron oxide reacts with carbon monoxide as follows:
Fe₂O3 + 3CO → 2Fe + 3CO₂
1 mole of Fe2O3 produces 2 moles of Fe
Moles of Fe = 187/56 = 3.34mol
3.34/2 = 1.67 moles of Fe2O3 will be required to produce 3.34 moles of Fe.
mass of Fe2O3 = 1.67 mol × 159.69 g/mol = 266.63g
Therefore, 266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
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