The standard deviation of the given discrete distribution, considering it's formula, is of 1.195.
Researching this problem on the internet, the distribution is given by:
Hence the mean is given by:
E(X) = 0.56(1) + 0.23(2) + 0.11(3) + 0.05(4) + 0.03(5) + 0.02(6) = 1.82.
The standard deviation is:
[tex]\sqrt{V(X)} = \sqrt{0.56(1-1.82)^2+0.23(2-1.82)^2+0.11(3-1.82)^2 + \cdots + 0.02(6-1.82)^2} = 1.195[/tex].
More can be learned about the standard deviation of a discrete distribution at https://brainly.com/question/13008984
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