Question

An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10s. assuming air resistance is negligible, calculate the initial velocity of the arrow, find also the height of the building

Answer 1

The initial velocity and the height of this building are 29 m/s and 780 meters respectively.

How to calculate the initial velocity?

In order to calculate the initial velocity, we would apply the second equation of motion:

S = ut - ½at²

200 = u10 - ½(9.8 × 10²)

200 = u10 - 490

u10 = 490 - 200

u10 = 290

u = 290/10

Initial velocity, u = 29 m/s.

Next, we would determine the height of the building:

H = ut + ½at²

H = 29(10) + ½(9.8 × 10²)

H = 290 + 490

Height, H = 780 meters.

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