Answer:
[tex]\frac{35\left( 1 + 35\right) }{2}[/tex]
Step-by-step explanation:
a(n) = n is an arithmetic sequence with first term a₁ = 1 and common difference r = 1.
Here we have to calculate the sum of the first 35 consecutive terms of an arithmetic sequence.
Using the formula for the sum ,we get :
[tex]\sum^{q}_{n=p} a_{n}=\frac{\text{number of terms} \times \left( \text{first term} +\text{last term} \right) }{2}[/tex]
Therefore
[tex]\sum^{35}_{n=1} n=\frac{35\left( 1 + 35\right) }{2}[/tex]
