Question

In(2e^9) in logarithmic expression

I’m having trouble with all of the “In” section and very confused

Answer 1

In logarithmic form, we get In(2e^9)= ln(2)+9.

Logarithms

• We define the logarithm as the power to which any number must be raised to get few other values.
• Exponentiation is the reverse process of logarithm.

We are given,

 ln(2$e^{9}$)

We know that, ln(ab) = ln(a) + ln(b)

So we get,

 ln(2$e^{9}$) = ln(2)+ln($e^{9}$)

Since ln(m^n)=n ln(m)  

And ln(e)= 1, we will get,

ln(2$e^{9}$) = ln(2) +9 ln(e)

          = ln(2) +9

Hence, the logarithmic form, we get In(2e^9)= ln(2)+9.

To learn more about Logarithms refer to:

https://brainly.com/question/20785664

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