Question

1-tan^2(x)/sec^2 = cos(2x)

Answer 1

By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1-$tan^{2} x$/$sec^{2}x$=cos2x.

Given: 1-$tan^{2} x$/$sec^{2}x$=cos2x.

Taking right hand side first which is cos2x.

We know that cos2x=$1-tan^{2}x/1+tan^{2}x$

Now we will solve the left hand side of the equation give which is

1-$tan^{2} x$/$sec^{2}x$

=1-$tan^{2}x$/1+$tan^{2}x$

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1-$tan^{2}x$/1+$tan^{2}x$.

Hence proved

Learn more about trigonometric functions at https://brainly.com/question/24349828

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