Question

A chopstick model of a catapult launches a marshmallow in a classroom. The path of the marshmallow can be modeled by the quadratic y=−0.07x2+x+2.2,

where y represents the height of the marshmallow, in feet,
and x represents the horizontal distance from the point it is launched, in feet.

When the marshmallow hits the ground, what is its horizontal distance from the point where it was launched?

Answer 1

The horizontal distance from the point where it was launched is 7.143.

We have given that,

The path of the marshmallow can be modeled by the quadratic y=−0.07x^2+x+2.2,

x represents the horizontal distance from the point it is launched, in feet.

What is the horizontal distance?

Horizontal distance means the distance between two points measured at a zero percent slope.

(1) Put x = 7.143 in given equation

y= -0.07(7.143)^2+7.143+2.2

y= 2.2

y= 5.771

We have to determine the what is its horizontal distance from the point where it was launched.

The value of x is called horizontal distance.

Therefore the horizontal distance from the point where it was launched is 7.143.

To learn more about the model visit:

https://brainly.com/question/593001

#SPJ1