Respuesta :
Answer:
C. (2, 0)
Step-by-step explanation:
The solution to this system of equations is the set of (x, y) values that satisfy both equations. It is the set of points where their graphs intersect.
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graph
A graph (attached) shows the only solution to be the point (2, 0), where the line is tangent to the parabola.
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algebraic
We can equate the two expressions for y to arrive at an algebraic solution.
x -2 = x² -3x +2
x -2 = (x -2)(x -1) . . . . factor the right side
0 = (x -2)(x -1 -1) . . . . subtract (x-2) from both sides
0 = (x -2)² . . . . simplify
x = 2 . . . . . . the only value of x that satisfies this equation
y = x -2 = 2 -2 = 0 . . . . the corresponding value of y
The one solution is (x, y) = (2, 0).

Given the system of equations: y=x-2 and y=x²-3x+2. The one solution is (x, y) = C. (2, 0). Option C is correct.
What is a system of equations?
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Given the system of equations:
y=x-2
y=x²-3x+2
A graph shows the only solution to be the point (2, 0), where the line is tangent to the parabola.
We can equate the two expressions for y;
x -2 = x² -3x +2
x -2 = (x -2)(x -1)
0 = (x -2)(x -1 -1)
0 = (x -2)²
simplify
x = 2
y = x -2 = 2 -2 = 0
Hence, The one solution is (x, y) = (2, 0). Option C is correct.
Learn more about equations here;
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