CD is the perpendicular bisector of both XY and ST, and CY = 16. Find TY.

The value of TY is 14
Given that CD is the perpendicular bisector of XY and ST and CY = 16
We need to find the value of TY
Here M is the midpoint of ST and D is the midpoint of XY
As shown in the diagram we can say that
CT = CS =12
We can also say that ST║XY
So , ∠CST = ∠CSY
∠CTS = ∠CYX
ΔSCT = ΔXCY
SX = CS - CX
= CY - CX
We can say that MT = SM = 5
DY = DX = 7
TY = SX = 4
CY = CX = 16
ST = SM + MT
ST= 5+5
∴ ST= 10
XY = XD +DY
XY = 7+7
∴ XY = 14
Hence the value of XY is 14
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