Question

Please help!!
Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation
(-4,5) y=1/3x +6

Answer 1

Answer:

The Equation of the line is y = $\frac{-1}{3}$x + $\frac{11}{3}$

Step-by-step explanation:

Multiplication of slope of two perpendicular lines is = -1

first line is  y= $\frac{1}{3}$x +6

slope of this line is $\frac{1}{3}$

So the slope of the second line is : $\frac{-1}{3}$

Equation of line would be written by using :

(y - y1) = m(x - x1)

here the line passing through (-4,5)

put the values in equation

y -5 =$\frac{-1}{3}$[x - (-4)]

3y - 15 = -x -4

3y = -x +11

y = $\frac{-1}{3}$x + $\frac{11}{3}$

So The Equation of the line is y = $\frac{-1}{3}$x + $\frac{11}{3}$

Learn more about Slope and Linear equation here - https://brainly.com/question/19744320

#SPJ10