Question

A tank holds 22.1 L of oxygen ( O2 ) at a pressure of 18.0 atm . What is the final volume, in liters, of this gas when it is released at a pressure of 2.90 atm with no change in temperature and amount of gas.

Answer 1

The final volume of gas will be 137.17L .

According to ideal gas equation , PV=nRT , where P is pressure of gas , V is volume of gas , n is moles of gas , R is universal gas constant and T is the temprature of gas.

Now , according to the que at initial and final stage the temprature and amount of gas stays constant , so we would simply equate the initial PV to the final PV.

⇒$P_{i} V_{i} = P_{f} V_{f}$

where $P_{i}$ ans $V_{i}$ are the initial pressure and volume of the gas and  $P_{f}$  and $V_{f}$ are the final pressure and volume of the gas .

Here we have to find final volume of gas .

So , putting all values in above eq we get

18 x 22.1 = 2.9 x  $V_{f}$

⇒ $V_{f}$ = 137.17 L

Learn more about ideal gas equation here https://brainly.com/question/25290815

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