Question

A scuba diver uses compressed air to breath under water. He starts with an air volume of 3.20 L at sea level (1 atm) at a temperature of 30°C. What is the volume of air in his tank at a depth of 100 ft (3 atm) and a temperature of 24°C?​

Answer 1

2.56 L is the volume of air in his tank at a depth of 100 ft (3 atm) and a temperature of 24°C.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$P_1=1 atm$

$V_1=3.20 L$

$T_1$=30°C

$P_2=3 atm$

$V_2=?$

$T_2=24°C$

Using the equation:

$\frac{P_1V_1}{T_1}$ =$\frac{P_2V_2}{T_2}$

$V_2$ =(1 atm x 3.20 L x 24°C) ÷ 30°C

$V_2$ = 2.56 L

Hence,  2.56 L is the volume of air in his tank at a depth of 100 ft (3 atm) and a temperature of 24°C.

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