The area bounded by the curves y = 8x – x² and y = 7 will be 36 square units.
The complete question is given below.
What is an area bounded by the curve?
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The curves are given below.
y = 8x – x²
y = 7
By solving the equations 1 and 2, then we have
8x – x² = 7
x² – 8x + 7 = 0
(x – 1)(x – 7) = 0
x = 1, 7
Then the area bounded by the curves y = 8x – x² and y = 7 will be
[tex]A = \int _1^7 [(8x - x^2) - 7] \ dx\\\\A = \left [ 4x^2 - \dfrac{x^3}{3} - 7x \right ]_1^7\\\\A = \left [ 4 * 7^2 - \dfrac{7^3}{3} - 7*7 \right ] - \left [ 4*1^2 - \dfrac{1^3}{3} - 7*1 \right ]\\\\[/tex]
On further solving we have
A = 32.667 + 3.333
A = 36 square units
More about the area bounded by the curve link is given below.
https://brainly.com/question/24563834
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