Question

PLS HELP I DONT KNOWWW!!

Answer 1

Answer:

3rd option

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (4, - 1) ← 2 points on the line

m = $\frac{-1-(-2)}{4-0}$ = $\frac{-1+2}{4}$ = $\frac{1}{4}$

the line crosses the y- axis at (0, - 2 ) ⇒ c = - 2

y = $\frac{1}{4}$ x - 2 ← equation of line

Answer 2

This can be solved using the gradient-intercept formula:

y = mx + c

where,
m is the gradient, and
c is the y-intercept (where the line crosses the y-axis)

Gradient can be calculated using the following formula, or rise/run:

m = (y2 - y1)/(x2 - x1)
= (-1 - - 2)/(4 - 0)
= 1/4

Therefore, using the gradient-intercept form:
y = mx + c
y = (1/4)x + (-2) (-2 is the point where the line crosses the y-axis)

Therefore, y = (1/4)x - 2 or Option C is the answer